Question

Help Please !!!
Each side of a square is increasing at a rate of 6 cm/ s . at what rate is the area of the square increasing when the area of the square is 12 cm ^2?

Answer 1

@Directrix

Answer 2

\[A = x^2\]
Differentiate with respect to time using the chain rule
\[\frac{dA}{dt} = \frac{dA}{dx} * \frac{dx}{dt}\]
\[\frac{dA}{dt} = 2x (6) = 12x\]
Finally when Area is 12, the side length (x) is sqrt(12)
\[\frac{dA}{dt} = 12 \sqrt{12} = 24 \sqrt{3}\]

Answer 3

okay then ?

Answer 4

my answer sheet says 48 how did they get that

Answer 5

48 is wrong its 24sqrt(3)

Answer 6

okay so then ty..

Answer 7

@satellite73 plz help me im confuse about this ..