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OpenStudy (simplymarie_x):
Check my answer? :-) What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 C and 0.980 atm? Answer: 12.0 L
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OpenStudy (simplymarie_x):
The steps I took: convert the temperature to K and use the formula V = nRT / P = (0.485 mol) x (0.08205746 L atm/K mol) x (23.0 + 273.15) K / (0.980 atm) = 12.0 L Can someone tell me if that's right?
OpenStudy (simplymarie_x):
@aaronq
OpenStudy (simplymarie_x):
@nincompoop @dtan5457 @TheSmartOne
OpenStudy (aaronq):
thats correct \(\huge \checkmark\)
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