Question

Check my answer? :-)

What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 C and 0.980 atm?

Answer: 12.0 L

Answer 1

The steps I took:

convert the temperature to K and use the formula
V = nRT / P = (0.485 mol) x (0.08205746 L atm/K mol) x (23.0 + 273.15) K / (0.980 atm) = 12.0 L

Can someone tell me if that's right?

Answer 2

@aaronq

Answer 3

@nincompoop @dtan5457 @TheSmartOne

Answer 4

thats correct \(\huge \checkmark\)