Question

here it is.... :))
@mathmath333

Answer 1

if a+b+c = 3x
Simplify
\[(x - a)^3 + (x + b)^3 + (x-c)^3 \]

Answer 2

\(\large \color{black}{\begin{align}
& (x - a)^3 + (x + b)^3 + (x-c)^3=3[(x - a)(x + b)(x-c)]\hspace{.33em}\\~\\
\end{align}}\)

Answer 3

next

Answer 4

if \[x^2 + x + 1 = 0 \]
evaluate
\[x^3 + \frac{ 1 }{ x^3 } = 0\]

Answer 5

lol but is my answer correct

Answer 6

@mathmath333 dont u think I would hav queestiond u if it was wrong -_-.... or u want me to write "Proud of u" lmoa....JK :P xD

Answer 7

ok

but the way havent u asked the second question before

Answer 8

really did I ...I dont think so

Answer 9

+2 is the answer

Answer 10

ooops my I really did ask tht before -_-
here
if
\[\frac{ a }{ b } + \frac{ b }{ a } = 1\]
evaluate
\[a^3 + b^3\]
too easy though :P

Answer 11

btw wo octagon wale ka soln post krna hai???

Answer 12

yes post the octagon that was interesting

Answer 13

http://prntscr.com/am3uty
see u get the fig ??

Answer 14

\(\large \color{black}{\begin{align}
& a^3 + b^3=0\hspace{.33em}\\~\\
\end{align}}\)

Answer 15

yes fig is easy

Answer 16

so let the edge lengt of octagon be = a
then
\[a = 11 - 2x = 13 -2y = \sqrt{x^2 + y^2}\]

and yeah thts correct

Answer 17

:) good one

Answer 18

lol yeah......
do u know the trick to solve
\[\sqrt{42+\sqrt{42+\sqrt{42+\sqrt{42........ \infty }}}}\]

Answer 19

7