@mathmath333
cool..... :)) this one is really good..... facotirse \[(x + 1)(x+2)(3x-1)(3x+4) + 12\]
other one...lets call it q no 2 \[a^{3-x}b^{5x} = a^{x+5}b^{3x} \] show that \[x~\log \frac{ b }{ a } = \log a\]
lol dont ask proofs it hurts
3)value of \[\frac{ \log \sqrt{27} + \log 64 + \log \sqrt{1000 }}{ \log 480 }\]
okkk I wont....btw where does it hurt :P
btw @mathmath333 rectangle area wala samajh aa gaya???
dont tell me I need to solve tht log question right now ... plzzz >_< I m not in mood -_-
r u sure this is factorable (x + 1)(x+2)(3x-1)(3x+4) + 12
ya obviously ...... so u doubting me..... take ur time..... I am gonna post few more questions and then .... gotta get ready ... 4)factorise \[x^2 - y^2 + 3x +- y + 2 \] 5)Let f(x) be a polynomial of degree equals or greater than 1. When f(x) is divided by (x-1) the remainder is 4 . When f(x) is divided by (x-2) remaindr is 9 and when divided by (x+1) remainder is 6. Wht would be the reaminder when f(x) is divided by (x-1)(x+2)(x-1) ??
i checked it wolf it is not factorable http://www.wolframalpha.com/input/?i=factor+%5B(x+%2B+1)(x%2B2)(3x-1)(3x%2B4)+%2B+12%5D
@hartnn hav a look over the question .... in which we are supposed to factorise :)) now I gtg ...so see ya..... in like 86400 secs ... :P
trust me it is factorable.... :)) wapas aa kr k batata hun .... :))
try another :))
ok i need to go to,,,, waiting
for that factorable que
lol yeah ....bt get me the answers of other questions.... :P try them out ....
ok
\(\large \frac{ \log \sqrt{27} + \log 64 + \log \sqrt{1000 }}{ \log 480 }=\frac{3}{2}\)
\(\large \color{black}{\begin{align} & x^2 - y^2 + 3x +- y + 2=(x-y+1)(x+y+2)\hspace{.33em}\\~\\ \end{align}}\)
tell me the soln of this one (x + 1)(x+2)(3x-1)(3x+4) + 12
good work .... :)) *claps. now I m going to college ..bye
and this one is unsolved for me "5)Let f(x) be a polynomial of degree equals or greater than 1."
@mathmath333 error report sorry..... heres the correct verios \[(x+1)(x+2)(3x-1)(3x-4)+12\]
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