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Mathematics 9 Online
OpenStudy (samirahsamirah):

I need help with this worksheet pleaseeee help!

OpenStudy (samirahsamirah):

OpenStudy (samirahsamirah):

Here's the worsheet

OpenStudy (jtug6):

For questions 1-4 do you know how to find the slope from a pair of points?

OpenStudy (samirahsamirah):

No i've been trying before i came on here

OpenStudy (jtug6):

Okay. Well, the slope from two coordinate points can be defined as m = \[(y _{2}-y _{1})/(x _{2}-x _{1})\]

OpenStudy (jtug6):

Where m is the slope, of course. And the pair of points can be (\[(x _{2}, y _{2}) and (x _{1},y _{1})\]

OpenStudy (jtug6):

You can choose either pair of points you were given to be 2 or 1, either will give you the same exact value.

OpenStudy (samirahsamirah):

So how do i do that?

OpenStudy (jtug6):

Okay so for #1, for instance. We're given (-5, -3) and (5, 4). I can say that x2 and y2 is (-5, -3) or (5, 4) either way they both work. I'll just say (-5, -3) is our (x2, y2) and that our (5, 4) is our (x1, y1). So now we know this: y2 = -3 y1 = 4 x2 = -5 x1 = 5

OpenStudy (jtug6):

Those 2's and 1's are supposed to be the tiny ones but it'd take me longer to write them out xD

OpenStudy (jtug6):

So, now we know that y2/y1/x2/x1 are all basically numbers, right? So plug them back into that equation that was given, which was: m = \[(y _{2}-y _{1})/(x _{2}-x _{1})\]

OpenStudy (jtug6):

So plug those numbers into that and you'll have your slope :)

OpenStudy (samirahsamirah):

im sorry but i'm confused i'm not so smart

OpenStudy (jtug6):

No, it's absolutely fine! Okay so look back at what i wrote. what was y2? wasnt that a number?

OpenStudy (samirahsamirah):

yes

OpenStudy (jtug6):

ok well what was it?

OpenStudy (samirahsamirah):

-3 i believe

OpenStudy (jtug6):

yes, and then what was y1?

OpenStudy (samirahsamirah):

4

OpenStudy (jtug6):

Ok so pop those back into the (y2 - y1). Wouldn't that just be -3 - 4?

OpenStudy (samirahsamirah):

yes

OpenStudy (jtug6):

great, so now we know thats -7. well we're dividing and we still have the bottom (denominator) to deal with. what was x2 and x1 again?

OpenStudy (samirahsamirah):

-5 and 5

OpenStudy (jtug6):

Sweet, so now we subtract those. -5 - 5 is -10 right? Well now we just divide.

OpenStudy (samirahsamirah):

so we divide -10 & -7?

OpenStudy (jtug6):

yep! so it's -7/-10 and thats the exact same as 7/10 cause the negatives cancel.

OpenStudy (jtug6):

and there you have it. that's your slope, or m.

OpenStudy (samirahsamirah):

i have 0.7

OpenStudy (jtug6):

that's acceptable as well. That's just 7/10 but in decimal form. :P

OpenStudy (samirahsamirah):

So i do the same format with number 1 to the rest 2,3, and 4

OpenStudy (jtug6):

Yep! Again you can pick either pair of coordinates to be your x2 and y2 and the other as your x1, y1 :P

OpenStudy (samirahsamirah):

Okay i'm going to do number 2 can you tell me of i got it right once i'm done?

OpenStudy (jtug6):

Ofc

OpenStudy (samirahsamirah):

First part I got is y2= -5 y1= 5 x2= 2 x1= -2

OpenStudy (jtug6):

Yep. Remember the formula and plug everything in. \[(y _{2}-y _{1})/(x _{2}-x _{1})\]

OpenStudy (samirahsamirah):

Them i add or subtract them?

OpenStudy (jtug6):

Definitely subtract, as you can see the minus from the formula.

OpenStudy (samirahsamirah):

then*

OpenStudy (samirahsamirah):

so -10 - -4?

OpenStudy (samirahsamirah):

equals -6

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