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Mathematics 14 Online
OpenStudy (anonymous):

help!!!

OpenStudy (scarlettfarra2000):

@Addya next time you should post the problem before going offline so that way people can help you

jigglypuff314 (jigglypuff314):

@ScarlettFarra2000 I believe they are using the app and are confused...

OpenStudy (scarlettfarra2000):

There's an app for this?

OpenStudy (anonymous):

there is but it's not great

OpenStudy (anonymous):

it's pretty hard to ask questions

jigglypuff314 (jigglypuff314):

here is the picture addya has tried sharing with us

OpenStudy (anonymous):

the question is on the attachment

jigglypuff314 (jigglypuff314):

addya, if you have a computer, you might have a better experience with getting a proper answer ^_^

jigglypuff314 (jigglypuff314):

I believe we are looking for \(b\) @addya are you aware of the Pythagorean Theorem? :) \(a^2 + b^2 = c^2\) in this case a = 3 and c = 5 and we are looking for b

OpenStudy (anonymous):

@jigglypuff314 that makes sense. I got b=4 as my final answer because the square root of 16 is 4. right?

jigglypuff314 (jigglypuff314):

@addya that is correct! good job!

OpenStudy (anonymous):

@jigglypuff314 may you help me with the others? I'm not sure I get it

jigglypuff314 (jigglypuff314):

of course ^_^ but please try attaching your pictures as a comment instead of in the actual question part, it helps us computer users see it better :)

OpenStudy (anonymous):

@jigglypuff314 my teacher wouldn't let us bring the book home. so I had to take pictures..

jigglypuff314 (jigglypuff314):

That's alright, the pictures are quite clear, thanks! This is the same idea with the Pythagorean Theorem \(a^2 + b^2 = c^2\) but this time a = 4 b = 4 and we are looking for c

OpenStudy (anonymous):

for question 4 or 5??

jigglypuff314 (jigglypuff314):

4

OpenStudy (anonymous):

I got to where I need the square root of 32. am I correct so far?

jigglypuff314 (jigglypuff314):

yes :)

OpenStudy (anonymous):

I guess I could leave it at c=the square root of 32

OpenStudy (anonymous):

that is what our teacher told us to do if there is no whole number as a square root

OpenStudy (l094n16):

Can I ask a question in here cause I can't get my "ask a question" to work

jigglypuff314 (jigglypuff314):

yes, then that would be correct great job!

jigglypuff314 (jigglypuff314):

@L094N16 try reloading your page, but please do not ask your question on someone else's post

OpenStudy (l094n16):

reloading it did zero good I already tried it.

OpenStudy (anonymous):

for number 5 I got x^2=the square root of 260

jigglypuff314 (jigglypuff314):

are you sure it's 260 and not 160? :)

OpenStudy (anonymous):

I meant 160. oops.. but is there a square root for that?

jigglypuff314 (jigglypuff314):

I believe you can simplify it to 4 times square root of 10

OpenStudy (anonymous):

I'm a little confused..

jigglypuff314 (jigglypuff314):

square root of 160 equals square root of 16 times 10 equals 4 times the square root of 10

OpenStudy (anonymous):

13

jigglypuff314 (jigglypuff314):

huh?

OpenStudy (anonymous):

oh my. I'm really confused on #5

jigglypuff314 (jigglypuff314):

you were right about square root of 160 I was just suggesting that you can simplify it to a weird 2 times square root of 10 but you don't have to :)

OpenStudy (anonymous):

okay.. so there is no whole number as the square root?

jigglypuff314 (jigglypuff314):

no there is not

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