Question

Will award medal and fan!
2NaOH + CO2 --> Na2CO3 + H20
There are 1.85 mol NaOH and 1.00 mol CO2
Question: How many moles of Na2CO3 can be produced??

Answer 1

Okay first thing you need to do is look up the molar masses of NaOH CO2 and Na2CO3

Answer 2

@lina777

Answer 3

@Photon336 NaOH=39.997
CO2=44.01
Na2CO3=105.9888

Answer 4

Thanks for helping by the way :)

Answer 5

So to do this we need to find out which reactant is the limiting reagent this means what reagent will run out first.

Answer 6

I already found this out, and it is the NaOH :)

Answer 7

let me double check this. take a look at what I do

Answer 8

\[1.85~mol~\cancel\NaOH*(\frac{ CO_{2} }{ 2\cancel\NaOH }) = NEED~0.925~mol~CO_{2}\]

Answer 9

\[1.0~mol~\cancel\CO_{2}*(\frac{ 2NaOH }{ mole~\cancel\CO2_{2} }) = NEED~2~mol~NaOH \]

Answer 10

We multiply the number of moles of each reactant that we HAVE by the molar ratio

Answer 11

now let's put it together. the molar ratio will tell us how much we need to react.
we compare this to how much we have

NEED
2 moles of NaOH
0.925 moles of CO2

HAVE
1.85 moles of NaOH
1.0 mole of CO2

so clearly we need 2 moles of NaOH but we only have 1.85 moles of NaOH
Therefore NaOH is going to run out first and so that's the limiting reagent.

so now the next step is

once we found out what our limiting reagent is (NaOH) we use this to figure out how much product we have.

Answer 12

\[1.85~\cancel\mol~\cancel\NaOH*(\frac{ mol~Na_{2}CO_{3} }{ 2\cancel\NaOH }) = 0.925~mol~Na_{2}CO_{3}\]

Answer 13

The way I set it up was this: You want to make sure that you multiply by the molar ratio. if you notice the compound you want to find is in the top the numerator while the compound you don't want is in the denominator and they cancel out.

Answer 14

This is great! Just a refresher, what do you mean when you say molar ratio?

Answer 15

sorry it's balanced I just checked

Answer 16

You can't do stoichiometry without balancing the equation.

Answer 17

you see those numbers the 2 in front of NaOH and the 1 in front of CO2?

Answer 18

Well molar ratio means the ratio of the number of moles of each compound in the balanced equation

Answer 19

Oh! Got it. Haha. I know what they are, I just forgot what they were called :)

Answer 20

Yeah no problem.

Answer 21

So, the final answer .925 mol Na2CO3? @Photon336

Answer 22

Yes

Answer 23

Okay! Thank you again!

Answer 24

No problem