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OpenStudy (theriverspirit):
In the following reaction what is oxided and reduced? what is the oxidizing reagent?
Mg+l2 -> Mgl2
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OpenStudy (photon336):
What do you think?
OpenStudy (theriverspirit):
i don't know can you explain it for me with the answer?
OpenStudy (photon336):
yes so whenever we have free elements like mg and I2 their oxidation states are 0
OpenStudy (photon336):
now oxidation means loss of electrons so the oxidation state will go up.
reduction means gaining of electrons so the oxidation state will go down.
OpenStudy (photon336):
just to see here.
\[Mg^{0} + I_{2}^{0} \rightarrow Mg^{2+}I^{2-}\]
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OpenStudy (theriverspirit):
so Mg^2+ is oxided?
OpenStudy (photon336):
yes and how do you know that?
OpenStudy (theriverspirit):
because the oxidation state went up when the reaction completed. Obviously I^2- means that it is the reduced. So whats the oxidizing agent?
OpenStudy (photon336):
yeah so oxidizing agent is the substance that causes the other to be oxidized
OpenStudy (photon336):
but is itself reduced
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OpenStudy (theriverspirit):
so I^2- is the oxidizing agent, correct?
OpenStudy (photon336):
\[I_{2} = oxidizing~agent \]
OpenStudy (theriverspirit):
thanks for the help
OpenStudy (theriverspirit):
i understand why I2 is the oxidizing agent and not I^2-
OpenStudy (photon336):
i2 is taking electrons from Mg and causing Mg to be oxidized to mg^2+
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OpenStudy (theriverspirit):
yeah
OpenStudy (photon336):
Mg is giving electrons to I2 and being oxidized.
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