Question

How does this model demonstrate the Pythagorean Theorem?

A. The sum of the lengths of the shortest and the longest sides is equal to twice the length of the middle side. So double the length of the longer leg of any right triangle is equal to the sum of the shorter leg and the hypotenuse.

B. The sum of the area of the two smaller squares is equal to the area of the larger square. So the sum of the lengths of the two legs of any right triangle squared is equal to the length of the hypotenuse squared.

Answer 1

C.
The sum of the area of the smallest and the largest squares is equal to the area of the middle square. So the sum of the lengths of the shorter leg and the hypotenuse of any right triangle squared is equal to the length of the middle leg squared.

D.
The length of the longest side minus two equals the length of the middle side. The length of the middle side minus two equals the length of the shortest side. So the length of the short leg of any right triangle is equal to the length of the middle leg minus 2, and the length of the hypotenuse is equal to the length of the middle leg plus 2.

https://static.k12.com/calms_media/media/1578000_1578500/1578333/1/83631eddd15e258c3a715d653ee6b23d0d38eb4b/MS_IMC-150120-1130201.bmp

Answer 2

@Photon336 @raffle-snaffle

Answer 3

what do you think it is

Answer 4

idk C?

Answer 5

if i tell you will you give me a medal

Answer 6

yes, but the answer has to be correct

Answer 7

it is C

Answer 8

I guarantee it is

Answer 9

It's actually a because a^2+b^2=c^2

Answer 10

oops ya it is A sorry man

Answer 11

hmmm A and C both have aspects that sounds correct

Answer 12

medal

Answer 13

please