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Mathematics 20 Online
OpenStudy (christos):

please help me how is this series converging ?? https://www.dropbox.com/s/ewm8pl948hljtoi/Screenshot%202016-04-02%2016.26.57.png?dl=0

OpenStudy (christos):

@Kainui

OpenStudy (kainui):

Might be good if you explain why you think it's not converging.

OpenStudy (anonymous):

first off \(5^3\)is just a number right it is \(125\)

OpenStudy (anonymous):

write as a fraction, you will see it

OpenStudy (kainui):

I can show you how to evaluate it too, although there are probably other ways of figuring it out. The main trick to evaluating it is this: \[(1-x)^{-1} = \sum_{k=0}^\infty x^k\]\[\frac{d}{dx} (1-x)^{-1} = \sum_{k=0}^\infty kx^{k-1}\]

OpenStudy (christos):

this is a geometric series with ratio = 5^3 * 1/6 ........ right ???? @Kainui

OpenStudy (kainui):

The ratio is \[\frac{a_{k+1}}{a_k}\]

OpenStudy (christos):

why not 5^3 * 1/6

OpenStudy (christos):

I thought if we keep multiplying 5^3 ( the first term) with the same thing above we get the series

OpenStudy (christos):

hence it being geometric

OpenStudy (christos):

has a common ration

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