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Mathematics 5 Online
OpenStudy (calculusxy):

Help in Algebra 1. MEDAL

DivineSolar (divinesolar):

Question?

OpenStudy (calculusxy):

OpenStudy (calculusxy):

I need help in the second part.

OpenStudy (faiqraees):

When the height of the object is going to decrease, the velocity is going to increase right?

OpenStudy (calculusxy):

The highest point that it can reach is at 2 seconds.

OpenStudy (faiqraees):

Since the GPE is being converted into Kinetic energy, the velocity of the object will increase

OpenStudy (faiqraees):

Thus the derivative of the function > 0 for the height to decrease

OpenStudy (calculusxy):

So what would be the time interval?

OpenStudy (welshfella):

after it reaches its maximum height it begins to fall to ground . The time it takes to fall to groun equals the time it takes to reach maximum height.

OpenStudy (faiqraees):

-32t+64> 0 solve for t

OpenStudy (faiqraees):

@welshfella Not necessary. What if the object is thrown from a some distance above the ground and this is true because at t= 0 h = 80

OpenStudy (calculusxy):

T = 2

OpenStudy (faiqraees):

so t>2 for the object's height to be decreasing

OpenStudy (calculusxy):

So it would be [2, \(\infty\))

OpenStudy (faiqraees):

Now they are asking for the reasoning. The reasoning is since it has reached its maximum height, the upward velocity is 0. But since the gravity is still acting on it, it would accelerate towards the earth and thus the distance would decrease

OpenStudy (calculusxy):

Thanks @FaiqRaees

OpenStudy (welshfella):

yes thats true

OpenStudy (faiqraees):

No problem

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