Join the QuestionCove community and study together with friends!
Sign Up
DivineSolar (divinesolar):
Question?
OpenStudy (calculusxy):
OpenStudy (calculusxy):
I need help in the second part.
OpenStudy (faiqraees):
When the height of the object is going to decrease, the velocity is going to increase right?
OpenStudy (calculusxy):
The highest point that it can reach is at 2 seconds.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (faiqraees):
Since the GPE is being converted into Kinetic energy, the velocity of the object will increase
OpenStudy (faiqraees):
Thus the derivative of the function > 0 for the height to decrease
OpenStudy (calculusxy):
So what would be the time interval?
OpenStudy (welshfella):
after it reaches its maximum height it begins to fall to ground .
The time it takes to fall to groun equals the time it takes to reach maximum height.
OpenStudy (faiqraees):
-32t+64> 0
solve for t
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (faiqraees):
@welshfella Not necessary. What if the object is thrown from a some distance above the ground and this is true because at t= 0 h = 80
OpenStudy (calculusxy):
T = 2
OpenStudy (faiqraees):
so t>2 for the object's height to be decreasing
OpenStudy (calculusxy):
So it would be
[2, \(\infty\))
OpenStudy (faiqraees):
Now they are asking for the reasoning. The reasoning is since it has reached its maximum height, the upward velocity is 0. But since the gravity is still acting on it, it would accelerate towards the earth and thus the distance would decrease
Still Need Help?
Join the QuestionCove community and study together with friends!