Question

3rd problem questions of the night
10 years ago

Answer 1

whats the question?

Answer 2

Good point lol it says to verify the identity

Answer 3

ok easy said than done lets start.. should we?

Answer 4

Okay! I am about to go bed soon so is there any way you could send me a walk through please? If not I understand

Answer 5

iill write everything here step by step

Answer 6

Thank you very very much :)

Answer 7

\[\frac{ 5 \sin x }{ 1+\cos x }\times \frac{ 1-\cos x }{ 1-\cos x }=\frac{ 5\sin x \left( 1-\cos x \right) }{ 1-\cos ^2x }=\frac{ 5\sin x \left( 1-\cos x \right) }{ \sin ^2x }\]
\[=\frac{ 5\left( 1-\cos x \right) }{ \sin x }\]

Answer 8

all done ::D

Answer 9

just in case you didnt understand that 13/sinx is 13csc, remember that 1/sinx is cscx

Answer 10

Thank you so very much, this helped me a lot. xoxo

Answer 11

np

Answer 12

\[\frac{ 8+5\cos x }{ \sin x }+\frac{ 5(1-\cos x) }{ \sin x }=\frac{ 8+5\cos x+5-5\cos x }{ \sin x }=\frac{ 13 }{ \sin x }=13\csc x\]

Answer 13

Surjithayer, is this just a different way of doing it than magepker did it?

Answer 14

first i have solved second term only
and made the denominator same as in first term.

Answer 15

same answer different approach, although @surjithayer 's is much faster, its technique used used when u master the basic step...

Answer 16

Its actually great that I have both of these so I can understand it from different ways. I really appreciate you both for taking the time to help me.

Answer 17

np anytime

Answer 18

yw