Question

if dy/dx = 2xy^2, and y(-1) = 2, find y(2)

Answer 1

separable differential equation

Answer 2

put x on one side and y on the other side of the equals sign then integrate.

Answer 3

I got as far as \[2\int\limits(y^2)dy=\int\limits(1/x)dx\]
then I integrated to get \[(2/3)y^3 = \ln \left| x \right|+ C\]
what now?

Answer 4

Since you are given y(-1) = 2 you can solve for C

Answer 5

X = -1 and y = 2

Answer 6

I solved for C and got (16/3) but my problem was in later plugging in y(2), the answer had to be either (a)4e^3 (b) -4e^3 (c) -3/2 (d) -2/5 or (e) -1/4

Answer 7

well we can' t take ln(-1)

Answer 8

ln(-1) = 3.14159265 i

Answer 9

@robtobey please help OP.

Answer 10

Your calculation is not correct