7 ln x=21... solve?
7lnx=21 lnx=3 x=e^3 =20.0855369
so... did we just decide the 7 isn't in the equation anymore?
you divide both sides by 7
\[\mathrm{Divide\:both\:sides\:by\:}7\] \[\frac{7\ln \left(x\right)}{7}=\frac{21}{7}\] \[\ln \left(x\right)=3\] \[\mathrm{Use\:the\:logarithmic\:definition:\quad }a=\ln \left(e^a\right)\] \[3=\ln \left(e^3\right)\] \[\ln \left(x\right)=\ln \left(e^3\right)\]
oooh right! Thank you so much!
\[\mathrm{When\:the\:logs\:have\:the\:same\:base:\:\:}\log _b\left(f\left(x\right)\right)=\log _b\left(g\left(x\right)\right)\quad \Rightarrow \quad f\left(x\right)=g\left(x\right)\] \[\mathrm{For\:}\ln \left(x\right)=\ln \left(e^3\right)\mathrm{,\:\quad solve\:}x=e^3\] \[x=e^3\] \[x=e^3\quad \left(\mathrm{Decimal:\quad }x=20.08554\right)\]
@study_buddy99 are you gotit
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