9^(x+5)=115 solve?
Do you mean \[9^{x+5} = 115\]
I honk this is the answer
Think
You set this up as a logarithmic equation. \[\log _{9}115=x+5 \] 2.15951167546=x+5 x=-2.84048832454
I got 109.7378886
www.mathway.com go there and put in the equation and u got ur answer medal and fan me pliz
@study_buddy99 its -2.84048832454
the answer is 115.2.3 -5
x= 2.15951167546-5 x=-2.84048832454
the answer is 115/2.3 -5
How did you calculate 109.73?
my calculator says so... one second
are you sure it's giving log base 9?
what mod warned me im not even sure if thats the correct answer
😀
To change the base you want to use \[Log_b(x)=\frac{Log(x)}{Log(b)}\] I think you did it in the wrong order maybe?
where log can be anything. Calculators usually have \[Log_e:=Ln, Log_{10}\]
Log can be base of anything that is.
now I got the answer -4.19
I get \[\frac{Log[115]}{Log[9]}=2.1595\], So 2.1592-5= -2.8405
I see, I was doing it backwards
:)
my two cents, I'd rather avoid change of base and just use natural log and properties of logs to solve. My first step would be \[9^{x+5}=115\\ln(9^{x+5})=ln(115)\\(x+5)ln9=ln(115)\] From there just solve for x. May save you time in the future :)
Also a good plan, and notice \[x+5=\frac{ln(115)}{ln(9)}\] shows up in @FibonacciChick666's solution, so you don't need to remember change of base formula, just derive it!
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