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Mathematics 15 Online
OpenStudy (study_buddy99):

9^(x+5)=115 solve?

OpenStudy (priyar):

Do you mean \[9^{x+5} = 115\]

OpenStudy (study_buddy99):

I honk this is the answer

OpenStudy (study_buddy99):

Think

OpenStudy (anonymous):

You set this up as a logarithmic equation. \[\log _{9}115=x+5 \] 2.15951167546=x+5 x=-2.84048832454

OpenStudy (study_buddy99):

I got 109.7378886

umerlodhi (umerlodhi):

www.mathway.com go there and put in the equation and u got ur answer medal and fan me pliz

OpenStudy (mtalhahassan2):

@study_buddy99 its -2.84048832454

umerlodhi (umerlodhi):

the answer is 115.2.3 -5

OpenStudy (mtalhahassan2):

x= 2.15951167546-5 x=-2.84048832454

umerlodhi (umerlodhi):

the answer is 115/2.3 -5

OpenStudy (anonymous):

How did you calculate 109.73?

OpenStudy (study_buddy99):

my calculator says so... one second

OpenStudy (anonymous):

are you sure it's giving log base 9?

umerlodhi (umerlodhi):

what mod warned me im not even sure if thats the correct answer

OpenStudy (study_buddy99):

😀

OpenStudy (anonymous):

To change the base you want to use \[Log_b(x)=\frac{Log(x)}{Log(b)}\] I think you did it in the wrong order maybe?

OpenStudy (anonymous):

where log can be anything. Calculators usually have \[Log_e:=Ln, Log_{10}\]

OpenStudy (anonymous):

Log can be base of anything that is.

OpenStudy (study_buddy99):

now I got the answer -4.19

OpenStudy (anonymous):

I get \[\frac{Log[115]}{Log[9]}=2.1595\], So 2.1592-5= -2.8405

OpenStudy (study_buddy99):

I see, I was doing it backwards

OpenStudy (anonymous):

:)

OpenStudy (fibonaccichick666):

my two cents, I'd rather avoid change of base and just use natural log and properties of logs to solve. My first step would be \[9^{x+5}=115\\ln(9^{x+5})=ln(115)\\(x+5)ln9=ln(115)\] From there just solve for x. May save you time in the future :)

OpenStudy (anonymous):

Also a good plan, and notice \[x+5=\frac{ln(115)}{ln(9)}\] shows up in @FibonacciChick666's solution, so you don't need to remember change of base formula, just derive it!

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