Question

higher roots problem? equation in replies

Answer 1

\[\sqrt[3]{x^7}\]

Answer 2

Answers:

\[x *\sqrt[3]{x^2}\]
\[x *\sqrt[3]{x}\]
\[x^3 * 3\sqrt x^2\]
\[x^2 * 3\sqrt x\]

Answer 3

Let me do an example for you!

\(\bf\Large \sqrt[4]{x^{13}} = \sqrt[4]{x^4 \times x^4 \times x^4 \times x}\)

\(\bf\Large = \sqrt[4]{x^4} \times \sqrt[4]{x^4} \times \sqrt[4]{x^4} \times \sqrt[4]{x}\)

\(\bf\Large = x \times x \times x \times \sqrt[4]{x}\)

\(\bf\Large = \boxed{\bf{ x^3\sqrt[4]{x}}}\)

Answer 4

So, basically, you need to factor the term inside in groups of what the nth root is. In my example, it was 4. In your question, it is 3.

Then you can take out as many of the groups as you can until you can't take anymore out.

Answer 5

Where'd the ^13 go? Is it x^4 13 times, and then simplified? o.O D:

Answer 6

Basically,

\(\bf\Large a^b \times a^c = a^{b+c}\)

So,

\(\bf\Large x^4 \times x^4 \times x^4 \times x = x^{4+4+4+1} = x^{13}\)

Answer 7

\(\large x^{13} = x^4 \times x^4 \times x^4 \times x = x^{4 + 4 + 4 + 1} = x^{13}\)