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Calculus help?
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@jim_thompson5910 @welshfella @robtobey @agent0smith
@Loser66
Anyone?
I'd start by finding the slope dy/dx at the given point.
3cos x?
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Okay... I'd start by carefully reading the question again. And then read my post above.
not sure can you explain?
Explain what...?
So, the equation: \[\frac{ dy }{ dx }=3\sin(x)\] Given the value of x, then dy/dx equals 3sin(x) at that particular point of x. For example, when x=16, then at the point where x=16, the gradient of y which is dy/dx=3sin(16). At the coordinate of the point on the graph where x=16 is (16, y(16)). The thing is, we don't know what y explicitly is, but we can tell what the gradient of y is at any point! Does that make better sense?
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