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Mathematics 12 Online
alones (alones):

Yo check this!

alones (alones):

\( \color{eneter color name}{3√n^75 } \)

OpenStudy (bobo-i-bo):

What about it? :P

alones (alones):

My answer was \( \color{eneter color name}{n^25} \)

jimthompson5910 (jim_thompson5910):

Is the problem this? \[\LARGE 3\sqrt{n^{75}}\] OR Is the problem this? \[\LARGE \sqrt[3]{n^{75}}\]

alones (alones):

I'm sorry if it's unclear .. B is my question

jimthompson5910 (jim_thompson5910):

So the problem is this? \[\LARGE \sqrt[3]{n^{75}}\] right?

jimthompson5910 (jim_thompson5910):

If so,then, \[\LARGE \sqrt[3]{n^{75}} = n^{75/3}\] \[\LARGE \sqrt[3]{n^{75}} = n^{25}\]

jimthompson5910 (jim_thompson5910):

which is what I think you meant to say when you posted your answer

alones (alones):

Oh I'm sorry again i mean A this time.. but i odn't have 3 as my exponent /:

OpenStudy (emmanuel77m):

Do you have an answer?

alones (alones):

Yep i got n^25

jimthompson5910 (jim_thompson5910):

Ok so if the problem is actually \(\Large 3\sqrt{n^{75}}\), then... \[\LARGE 3\sqrt{n^{75}} = 3\left(n^{75}\right)^{1/2}\] \[\LARGE 3\sqrt{n^{75}} = 3n^{75/2}\] \[\LARGE 3\sqrt{n^{75}} = 3n^{74/2}*n^{1/2}\] \[\LARGE 3\sqrt{n^{75}} = 3n^{37}*n^{1/2}\] \[\LARGE 3\sqrt{n^{75}} = 3n^{37}\sqrt{n}\]

alones (alones):

Oh.. thanky you jim.. i think i'm blind didn't see it

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