Question

WILL FAN AND MEDAL
What is the measure of angle J in the triangle below? Drawing is not to scale.

Answer 1

I really don't understand this and need help, if someone can guide me through it, or someone has done this. Please and thank you!

Answer 2

Do you know the law of sines?

Answer 3

I know that Sine=Opposite/Hypotenuse

Answer 4

\[\frac{ \sin(103) }{ 16 }=\frac{ \sin(J) }{ 11 }=\frac{ \sin(K) }{ JL}\]

Answer 5

okay, so you have:
\[\frac{ \sin(103) }{ 16 }=\frac{ \sin(J) }{ 11 }\]
In this equation, you have only one unknown. Can you see that? Can you see what to do?

Answer 6

So I just have to find the variable, J, now, right?

Answer 7

I believe that is what the question is asking for after all, yes :P

Answer 8

And do you know how to find J?

Answer 9

Cross multiply, and then go from there?\[11 \times \sin(103) = 16 \times \sin(J)\]

Answer 10

That is absolutely valid, yes. Continue ^_^

Answer 11

https://gyazo.com/44679c55825358a2a353d5e403cdbac3

I got this a 0.66988.... But I don't know what to do with the sin part of J??

Answer 12

Does anyone know what to do??

Answer 13

https://www.mathsisfun.com/algebra/trig-inverse-sin-cos-tan.html

Answer 14

Y'all are overcomplicating this:
\[\frac{ 16 }{ \sin(103) } =\frac{ 11 }{ ? }\]

Answer 15

That's what I did, except the fractions were in reverse, and if you cross multiply, you get the same thing, 0.67, and I think yuour suppose to do asin(0.67) i.e. sin^-1 (0.67)

I seriously have no idea, if that is right, because that equals 42.067...

Answer 16

@Ms-Brains

Answer 17

@kayders1997 Can you please help my friend here?

Answer 18

Sorry, Girl I got no clue.

Answer 19

K, thanks anyway :)

Answer 20

You have to take the inverse sin

Answer 21

Here let me try quick

Answer 22

GURRRRLLLLLLLLL
lemme help ya out:
"I seriously have no idea, if that is right, because that equals 42.067..."

42 degrees ;)

Answer 23

Yeah, I did asin on the calculater, which is the inverse, but I don't know if it is correct

Answer 24

That is what I got

Answer 25

What did you get?

Answer 26

Make sure your calculator is in degree mode

Answer 27

Than cross multiply

Answer 28

https://gyazo.com/f520fde89b1c9126833c5e4970fa3a28

That's what I got

Answer 29

Yay :)

Answer 30

Thanks @Aveline

Answer 31

And @kayders1997

Answer 32

I just wanted to be sure :)

Answer 33

We're here to help :) if you need help you can always comment my name :)

Answer 34

K, thanks, I'll close this and tag ya'll if I have another hard question :)

Answer 35

Sounds good :)