Will Give Medal!

A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second. What is the maximum height of the particle?

100 feet
96 feet
60 feet
56 feet

Question

Will Give Medal!

A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second. What is the maximum height of the particle?

 100 feet
 96 feet
 60 feet
 56 feet

hannahwaller5 · Answer

@anthonyym

taylarm7 · Answer

100 feet

hannahwaller5 · Answer

Do you know how? I am confused on how to get the answer...

taylarm7 · Answer

do you want me to put the equation of how I found it?

anthonyym · Answer

Ok, this is the formula sheet which I find helpful: http://plaza.obu.edu/corneliusk/ps/phys/kelm.pdf

anthonyym · Answer

Vf = final velocity
Vi = initial velocity
a = acceleration
t = time
$$\Delta x$$ = displacement

hannahwaller5 · Answer

ok...  so is there a formula i need to use?

anthonyym · Answer

The formula would be $$Vf^2 = Vi^2 + 2a \Delta x$$
Vf = 0, because final y-velocity at an object's maximum height is 0.
Vi = 16ft/s
a = 32ft/s^2, this is the acceleration due to gravity
x = ?, what you have to find.

And after you find x, remember to add 96ft to your final answer because the object started at 96ft