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Mathematics 15 Online
OpenStudy (shaleiah):

@anthonyym

OpenStudy (shaleiah):

The length of one side of a shoebox is 8 cm more than twice the width. The base of the shoebox has an area of 72 cm^2. Write an equation to represent this situation with w representing the width.

OpenStudy (anthonyym):

So we need to translate the words into an equation. "length of one side of a shoebox is 8 cm more than twice the width" Let l be length, w be width. l = 2w + 8 And area = length*width

OpenStudy (anthonyym):

Do you understand the l = 2w + 8 part?

OpenStudy (shaleiah):

Shouldn't it be flipped? 8+2w

OpenStudy (anthonyym):

Yes it doesn't matter 8+2w is the same as 2w+8 because order doesn't matter in addition.

OpenStudy (anthonyym):

I was just keeping it consistent. You know sometimes they say "8 less than w" and it would be w - 8

OpenStudy (shaleiah):

You have a point, thanks!

OpenStudy (anthonyym):

So it says the area is 72 cm^2, and area for a rectangle is length*width, so the equation for this would be: 72 = lw

OpenStudy (anthonyym):

And the other equation we have is l = 2w + 8. So we need to put the two into one equation.

OpenStudy (anthonyym):

Have a thought on how to combine l = 2w + 8, 72 = lw into one equation?

OpenStudy (shaleiah):

2w+8w=72

OpenStudy (anthonyym):

Yes that's so close actually. You're substituting l = 2w + 8 for the l in 72 = lw, so you have: 72 = (2w + 8)w = 72. When you distribute the w into 2w, 2w becomes 2w^2. Think that was the mistake.

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