Question

Convert 3 – 3i to polar form.

Answer 1

https://answers.yahoo.com/question/index?qid=20110221124237AAlBC7Q

Answer 2

i dont know how to do this but look at the website it might help u;)

Answer 3

Let 3-3 i=r(cos theta+i sin theta)
\[r ~\cos \theta=3\]
\[r \sin \theta=-3\]
square and add
\[r^2\left( \cos ^2\theta+\iota \sin ^2\theta \right)=3^2+(-3)^2=9+9=18=9 \times 2,r=3\sqrt{2}\]
cos is positive and sin is negative so \[\theta\] lies in fourth quadrant.
divide\[\tan \theta=\frac{ r \sin \theta }{ r \cos \theta }=\frac{ -3 }{ 3 }=-1=- \tan 45=\tan \left( 360-45 \right) =\tan 315\]
\[\theta =315\]
now you can write.