A ball's position, in meters, as it travels every second is represented by the position function s(t) = 4.9t2+ 350. Include units in your answer. What is the velocity of the ball after 2 seconds?
\[velocity~ v=\frac{ ds }{ dt }=2 \times 4.9 t=9.8 t\] plug t=2 and get the answer.
Is the answer 19.6?
@Aveline
Is that correct @anthonyym?
This is my guess on it: The formula is already given: s(t) = 4.9t^2+ 350 Just plug 2 as t to get s(t), which is position. You get 369.2 as s(t). Velocity is distance/time. Distance is 369.2. Time is 2, so Velocity is 184.6
Yes but when you plug in that problem and solve for the derivative you get 9.8. so which way is correct?
Well I'm not in calculus, but my physics teacher told me that derivative is the slope. The slope of a position v. time graph is velocity and slope of velocity v. time is acceleration. Acceleration due to gravity is 9.8
Ohh okay. I will put both in my answer and I will let my teacher tell me which one is correct. Thank you.
https://www.algebra.com/algebra/homework/Finance/Finance.faq.question.1000671.html Or check this example out, it says "velocity is the first derivative of displacement"
Yeah, my answer is probably wrong because the slope of the graph is not constant. You have to find the slope of the graph at t=3 with calculus probably which gets the velocity.
19.6 is correct.
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