Question

Prove that the area of triangle ABC can be found from:

Answer 1

\[0.5 * c^2 * \frac{ \sin a \sin b }{ \sin (a+b) }\]

Where should I start? I'm trying to transform the equation 1/2 ab sin c = area to this equation but I'm not succeeding.

Thanks in advance!

Answer 2

need help

Answer 3

Yes please! I might poof but that's because lunch is coming up shortly. c:

Answer 4

its 7:10 XD

Answer 5

it's 2 pm where I am.

But seriously, do you have any hints? I'm struggling. :c

Answer 6

hmm is it ok if i invite friend 2 help homie

Answer 7

@pink33

Answer 8

@ganeshie8

Answer 9

@MeganXOXO

Answer 10

I'm here

Answer 11

need help with this

Answer 12

@kathryn.goodnight

Answer 13

@knov

Answer 14

@Kicker71

Answer 15

@SageWilson

Answer 16

what do you need help with?

Answer 17

I would start by drawing the triangle, inside the rectangle (remember that the altitude h is perpendicular to the base b).

Answer 18

@Miracrown

Answer 19

First, you can say that the area of the rectangle is hb. Then you can reason that the triangle's area is ½hb since it neatly divides the rectangle into two pairs of congruent triangles.

Now look at the right triangle I've shaded. Can you find an expression for h in terms of a and C? If so, replace h in the ½hb calculation and you will have proved the solution.

Answer 20

http://mathcentral.uregina.ca/QQ/database/QQ.09.07/s/eileen1.1.gif

Answer 21

@pink33 I assume he wants to solve it using the equation he is given.

Answer 22

oh,okay

Answer 23

sorry for the delay! I'm going to read your responses now. c:

Answer 24

I wasn't given that equation to be frank, I just assumed I should start from there. c@

Answer 25

thank you pink! I think you've given men the key to solving this. c;