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Mathematics 10 Online
OpenStudy (neverendingcycle):

I need help! Look at the picture for the problems

OpenStudy (neverendingcycle):

OpenStudy (anonymous):

Question one is 0.1

OpenStudy (neverendingcycle):

i need some proof just to make sure

OpenStudy (mythorius):

@mathstudent55

OpenStudy (mythorius):

@KendrickLamar2014

OpenStudy (mythorius):

@TheSmartOne

OpenStudy (anonymous):

Bring the equations in this form: y=ax^2. a will be your answer.

OpenStudy (neverendingcycle):

for what number 1 or 2?

OpenStudy (anonymous):

No I meant the variable 'a' in the equation y=ax^2 will be your answer. Not the option a. Sorry for the confusion.

OpenStudy (neverendingcycle):

Its okay

OpenStudy (neverendingcycle):

The equation is 7y=.28x^2 though on number 1. I answered with .28 and I got it wrong last time.

OpenStudy (anonymous):

For example, in question 1: 0.1y = 3x^2. When we convert it to the form I was saying we get" y= (3/0.1) x^2. Now 3/0.1 is your constant of variation. Now try question 2 again with this method, you will get the right answer

OpenStudy (neverendingcycle):

OHHHHHHHHH its that easy?!!?!?!? wow thanks a lot my teacher failed to mention that

OpenStudy (anonymous):

No problem. So, just to be sure, what did you get for question 2?

OpenStudy (neverendingcycle):

so its .01/3 or 3/.01? just making sure you typed it right

OpenStudy (anonymous):

Nope, I typed it right :) Basic idea is, there should be no numbers next to y. You need to find what is the constant that drives the value of y dependent on x. So, move everything tied to y over to x side. Now whatever constant is left next to x^2 is your constant of variation. For question 1, it will be 3/0.1 = 30. Try question 2.

OpenStudy (neverendingcycle):

okay for question 2 I got 0.04

OpenStudy (neverendingcycle):

(btw i need it in decimal format not fraction)

OpenStudy (anonymous):

Thats exactly right! 0.28/7 = 0.04

OpenStudy (neverendingcycle):

this one

OpenStudy (anonymous):

ok fairly straight forward. f(x) = ax^2. Now plug in the value of x as 6, and equate the equation to 144 to find the value of a. You will have your expression.

OpenStudy (neverendingcycle):

so g(x)=24x^2

OpenStudy (anonymous):

Thats not correct. Just solve this equation for a: \[a \times x ^{2} = 144\]

OpenStudy (anonymous):

and forgot to mention, plug in x = 6

OpenStudy (neverendingcycle):

im confused now

OpenStudy (anonymous):

hmm sorry to confuse you. Let me try this way: 144 = a*x^2 144 = a*6^2 144 = a*36 a = 144/36 a = 4 Any clearer?

OpenStudy (neverendingcycle):

yes, much thanks you!

OpenStudy (anonymous):

No problem.

OpenStudy (neverendingcycle):

Could you check my answer?

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