I need help! Look at the picture for the problems
Question one is 0.1
i need some proof just to make sure
@mathstudent55
@KendrickLamar2014
@TheSmartOne
Bring the equations in this form: y=ax^2. a will be your answer.
for what number 1 or 2?
No I meant the variable 'a' in the equation y=ax^2 will be your answer. Not the option a. Sorry for the confusion.
Its okay
The equation is 7y=.28x^2 though on number 1. I answered with .28 and I got it wrong last time.
For example, in question 1: 0.1y = 3x^2. When we convert it to the form I was saying we get" y= (3/0.1) x^2. Now 3/0.1 is your constant of variation. Now try question 2 again with this method, you will get the right answer
OHHHHHHHHH its that easy?!!?!?!? wow thanks a lot my teacher failed to mention that
No problem. So, just to be sure, what did you get for question 2?
so its .01/3 or 3/.01? just making sure you typed it right
Nope, I typed it right :) Basic idea is, there should be no numbers next to y. You need to find what is the constant that drives the value of y dependent on x. So, move everything tied to y over to x side. Now whatever constant is left next to x^2 is your constant of variation. For question 1, it will be 3/0.1 = 30. Try question 2.
okay for question 2 I got 0.04
(btw i need it in decimal format not fraction)
Thats exactly right! 0.28/7 = 0.04
this one
ok fairly straight forward. f(x) = ax^2. Now plug in the value of x as 6, and equate the equation to 144 to find the value of a. You will have your expression.
so g(x)=24x^2
Thats not correct. Just solve this equation for a: \[a \times x ^{2} = 144\]
and forgot to mention, plug in x = 6
im confused now
hmm sorry to confuse you. Let me try this way: 144 = a*x^2 144 = a*6^2 144 = a*36 a = 144/36 a = 4 Any clearer?
yes, much thanks you!
No problem.
Could you check my answer?
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