Question

Will FAN & MEDAL! PLS HELP

The height, h (in meters above ground), of a projectile at any time, t (in seconds), after the launch is defined by the function h(t) = −3t^2 + 11t + 4. The graph of this function is shown below. When rounded to the nearest tenth, what is the maximum height reached by the projectile, how long did it take to reach its maximum height, and when did the projectile hit the ground?
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Answer 1

A- The projectile reached a maximum height of 13.5 meters in 1.5 seconds and it took 3.6 seconds for it to hit the ground.

B- The projectile reached a maximum height of 13.9 meters in 1.5 seconds and it took 3.9 seconds for it to hit the ground.

C- The projectile reached a maximum height of 14.1 meters in 1.8 seconds and it took 4.0 seconds for it to hit the ground.

D- The projectile reached a maximum height of 1.8 meters in 14.1 seconds and it took 4.0 seconds for it to hit the ground.

Answer 2

If you take the derivative of that equation and equate it to 0, that will give you the value of t at maximum height. You can check if its the maximum value, by taking 2nd derivative and ensuring the value is negative.
Once you have t taken to reach maximum height, just plug it in the equation to get the actual height.

If this doesn't clear things up, let me know.

Answer 3

It does, a lot actually thanks a lot