Question

please help!!!
P4 + 6CI2 =4PCI3

If 5 moles of P4 reacted with 22 moles CI2 according to the reaction above, determine:
a. How many moles PCI3 are produced.

b. How many moles of P4 are left in excess after the reaction (if any)

c.How many moles of CI2 are left in excess after the reaction (if any)

Answer 1

Well, P4 is the limiting reagent because it have a lower number of mols. Cl2 is, on the other hand, in excess
And the ratio of P4 and PCl3 is 1:4, so 5 * 4 = the mol of PCl3

Answer 2

so theres 20 moles of PCI3 produced??

Answer 3

Yes

Answer 4

can you explain to me again how you get the 20 moles on the first one??

Answer 5

can you explain it to me instead??

Answer 6

Apparently I did something wrong.. I think we need to find out which one is the limiting factor by making both reactants one mole.

The mole ratio between P4 and Cl2 is 1:6
So P4 is 5 moles
and Cl2 is 22/6 is 3.667 moles
Therefore Cl2 is the limiting reagent instead.
So if this is the case, PCl3 is 3.667*4.

Answer 7

So this changes the answers for b and c

Answer 8

step #1 make sure the reaction is balanced

step #2 then identify the limiting reagent.

Answer 9

where did you get the 6??

Answer 10

by getting both P4 and Cl2 into 1:1 ratio to identify the limiting reagent.

Answer 11

You need to multiply the number of moles of each reactant by the molar ratio.

Answer 12

?? still dont get it

Answer 13

cus you said to get to 1:1 ratio but it has 1:6

Answer 14

It is just to find out the limiting reagent. The smallest one is. The ratios of the equation still pertains

Answer 15

You then you the ratio to calculate the mols for PCl3