If f(x) varies directly with x^2, and f(x) = 75 when x = 5, find the value of f(8).
(I can find the answer but I need help putting the equation together)
A. 192
B. 25
C. 256
D. 40
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OpenStudy (neverendingcycle):
@Compassionate @Luigi0210
OpenStudy (luigi0210):
Varies directly meaning it would look something like this: \(\ y=kx \)
OpenStudy (luigi0210):
In your case, it would be \(\large f(x)=kx^2\)
OpenStudy (neverendingcycle):
what does k stand for again?
OpenStudy (neverendingcycle):
constant something I think?
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OpenStudy (luigi0210):
Yes, it's the constant you're solving for in the equation.
OpenStudy (neverendingcycle):
so its 75=k5^2?
OpenStudy (luigi0210):
Once you plug in all the information given \(\large 75 = k (5)^2 \)
You solve for "k"
Once you get k you can plug it back in with the new condition \(\large f(8) \)
OpenStudy (neverendingcycle):
so then it becomes f(8)=3x^2?
OpenStudy (neverendingcycle):
or is the x still 5?
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OpenStudy (luigi0210):
* \(\large f(x)=3x^2 \)
But yes, then you just plug in "8" for "x" as \(f(8) \) dictates.
\(\large f(8)=3 (8)^2 \) and that will give you your solution (:
OpenStudy (neverendingcycle):
ohh okay thanks a bunch!
OpenStudy (luigi0210):
No prob :P
OpenStudy (neverendingcycle):
i got 192
OpenStudy (luigi0210):
You would be correct.
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