If f(x) varies directly with x^2, and f(x) = 75 when x = 5, find the value of f(8). (I can find the answer but I need help putting the equation together) A. 192 B. 25 C. 256 D. 40
@Compassionate @Luigi0210
Varies directly meaning it would look something like this: \(\ y=kx \)
In your case, it would be \(\large f(x)=kx^2\)
what does k stand for again?
constant something I think?
Yes, it's the constant you're solving for in the equation.
so its 75=k5^2?
Once you plug in all the information given \(\large 75 = k (5)^2 \) You solve for "k" Once you get k you can plug it back in with the new condition \(\large f(8) \)
so then it becomes f(8)=3x^2?
or is the x still 5?
* \(\large f(x)=3x^2 \) But yes, then you just plug in "8" for "x" as \(f(8) \) dictates. \(\large f(8)=3 (8)^2 \) and that will give you your solution (:
ohh okay thanks a bunch!
No prob :P
i got 192
You would be correct.
Yes!
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