Question

Integration Review Help

Answer 1

to find the area under the graph you use the trapezium rule
(10/2)x [17+17+ 2x(20+22+21)]
=328 SQUARE UNITS

Answer 2

OKay yeah I thought that was the way to do it but I wasn't sure

Answer 3

Do you want help with all the questions?

Answer 4

Yeah if that ain't a problem

Answer 5

I'll be here tomorrow and Friday so doesn't have to be all today

Answer 6

okay

Answer 7

So that first one was for part a of the first question right?

Answer 8

Could you write that first expression with the equation maker thing it is hard to see what values you are multiplying/adding

Answer 9

For part A it's just the average speed value from 6:00 to 6:40 so (17+20+22+21+17) /5=82.4mph

Answer 10

Is that really it? Wow I thoguht I would have to at least use the average value function

Answer 11

the trapezium rule is Area=(perpendicular height of trapezium/2) x (extreme lengths + 2x[lengths in between added together])

Answer 12

Okay

Answer 13

I don't know how to do part A i thought i would use the mean but it said use the trapezoid rule so...

Answer 14

That's okay

Answer 15

Are you a student?

Answer 16

I'm a UK student the curriculum is a bit different

Answer 17

Calculus?

Answer 18

This is calculus

Answer 19

Yeah we are taught calculus. For the trapezium rule we are only taught how to estimate the area under the curve

Answer 20

Yeah Okay cool we call it trapezoidal, but it's the same thing
And that was last quarter so that isn't what I'm supposed to do in this question

Answer 21

Shoot dude I have to go I'll "see" you later

Answer 22

ok