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OpenStudy (marcelie):
OpenStudy (marcelie):
NUMBER 74
OpenStudy (marcelie):
@satellite73
OpenStudy (anonymous):
\[\huge y=x^{\frac{5}{x}}\]?
OpenStudy (marcelie):
yes
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OpenStudy (anonymous):
you have a choice
you can write what this actually is, i.e. \[\huge x^{\frac{5}{x}}=e^{\frac{5}{x}\ln(x)}\] and take the derivative of that one using the chain and product rule
OpenStudy (marcelie):
question how did u get the left side
OpenStudy (anonymous):
or, as your math teacher might say
"take the log"
get \[\ln(x^{\frac{5}{x}})=\frac{5}{x}\ln(x)\] then take the derivative of that, then multiply again by the original function
the work is identical
OpenStudy (anonymous):
you mean how did i get the right hand side?
OpenStudy (marcelie):
yes
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OpenStudy (marcelie):
im lost D:
OpenStudy (anonymous):
the definition of \(b^x\) is \[\huge b^x=e^{x\ln(b)}\]
OpenStudy (anonymous):
ok lets not do it that way if it confuses you, lets do it the math teacher way
do you have a math teacher?
OpenStudy (marcelie):
yes her lectures are so confusing lol
OpenStudy (anonymous):
ok so the idea is this
you know that the the derivative of \(\ln(x)\) is \(\frac{1}{x}\) right?
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OpenStudy (marcelie):
yes
OpenStudy (anonymous):
and by the chain rule, the derivative of \[\ln(f(x))=\frac{f'(x)}{f(x)}\] yes?
OpenStudy (marcelie):
yes
OpenStudy (anonymous):
so you do this
you have a function you need to find the derivative of
you take the log of that function
then take the derivative of the log
then multiply by the original function at the end