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Solve for theta y=cos(theta/2)
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\[\theta=2\cos^{-1}(y)\]
They are the same thing, so it's true for all angles theta
The actual question itself has more components. \[x=\sin \frac{ 1 }{ 2 }\theta, y=\cos \frac{ 1 }{ 2 }\theta\] I want to write it either in terms of y or x \[\theta=2\cos^{-1}(y) \]\[x=\sin \frac{ 1 }{ 2 }*2\cos^{-1}(y)\]\[x=\sin(\cos^{-1}(y))\]
@larryboxaplenty what is true? o_o
Once we know theta can't we just plug it into x and simplify?
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The question: "Eliminate the parameter to find a Cartesian equation of the curve" \[-\pi \le \theta \le \pi\] then look up a few comments for the rest of the question xD
wait how did you get rid of sin and y?
wouldn't \[x=\sqrt{1-y^2}\]
Yeah. I think it is.
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