From an urn containing 6 balls,3 white and 3 black ones, a lerson select at random an even nunber of balls (all the different ways of drawing an even number of balls are considered equally probable, irrespective of number). Then the probability that there will be the same number of black and white balls among them is
Person*
@ganeshie8
hey
Hello! Would you pls help?
I actually added up the probability when he draw 2 balls ,4 balls and 6 balls..
For two balls v can write that it shud be 3C1*3C1/6C2
@ganeshie8 will u help?
@knov
wait a sec. i on the other question.
okay, so there are 3 even numbers in number 6.
2, 4, 6. the person will select randomly from these numbers.
from here we are looking for the probability of same number of black and white balls.
Yes ..he can either select two or four or six balls out of the bag
yes.
lets look at the case in which the random even number is 4
in this case have four over four combinations.
3C2*3C2 is favourable case
we*
6C4 r total cases.
you mean including the all cases ?
* symbol is for multiplication
No ! Just drawing four balls out of 6
yes, you are correct.
So u intend to say this that probability of drawing four balls out of 6 is 3C2*3C2/6C4 Similarly we can solve for the rest two cases where balls drawn are two or six
and then we shud add them all to get the ans
no, that would be just one tho.
i just miscalculated it. sry
it's 6^four
so here we are looking for all b b w w cases.
Did u read my last post ?
Is that what u want to do next?
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