Question

Help Please !!
75 and 76

Answer 1

\[\large \bf lnxy=4ysinx\]
use implicit differentiation

Answer 2

@zepdrix

Answer 3

can you help me with 75.

Answer 4

\[\large\rm \ln(xy)=4y(sinx)\]

Answer 5

how do i do the implicit form ?

Answer 6

You're differentiate each side, with respect to x,
\[\large\rm \frac{d}{dx}\ln(xy)=\frac{d}{dx}4y(sinx)\]on the left side, we have log rule, into chain rule,\[\large\rm \frac{1}{xy}\cdot(xy)'=\frac{d}{dx}4y(sinx)\]