Related Rates question.

Water is being poured into a cone-shaped container. When the depth of the water is 2.5 inches, it is increasing at 3 in/min. At that time, how fast is the surface area, A, that is covered by water increasing?

The hint given in the book says A = pi*r*s, which I assume is for the area covered in water.

Question

Related Rates question.

Water is being poured into a cone-shaped container. When the depth of the water is 2.5 inches, it is increasing at 3 in/min. At that time, how fast is the surface area, A, that is covered by water increasing?

The hint given in the book says A = pi*r*s, which I assume is for the area covered in water.

phi · Answer

Yes, the "lateral area"  of a cone is given by A = pi*r*s  where s is the 'slant height"
|dw:1460031255205:dw|