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Solve: sec^2x-secx=2
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First, multiply the entire equation by cos^2 (x). This gives 1 - cos(x) = 2cos^2 (x). Then, let u = cos (x) so we have 2u^2 = 1-u. This gives u = -1 & u = 1/2. Now, we put these solutions in terms of x by letting cos (x) = -1 and cos (x) = 1/2. For x in [0, 2 pi): cos(x) = -1 ==> x = pi. cos(x) = 1/2 ==> x = pi /3 and x = 5 pi /3. So x = {pi/3, pi, and 5 pi/3} are the three solutions to this equation in [0, 2 pi).
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