Question

help?

Answer 1

Alright so we have the standard form

\[\large \frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1\]

Meaning we have

\[\large \frac{x^2}{2500} + \frac{y^2}{8100} = 1\]

Making a = 50 and b = 90 right?

Answer 2

.....patiently awaiting your answer >:P

Answer 3

Okay..?

Answer 4

Actually I should ask right away...how would you go about this problem?

Answer 5

Wait john what do you mean?

Answer 6

we're trying to find the length of the track.

Answer 7

Just the length of the major axis of the track :)

Answer 8

Ohh okay... but whats the next step...

Answer 9

90^2 was the 1800??? no.

Answer 10

*8100

Answer 11

So now we're looking for h and k.

Answer 12

Okay well the FIRST step would have been to say I was WRONG!

I said a = 50 and b = 90

BUTTTTT we should know a is the larger of the 2 denominators

\[\large \frac{x^2}{50^2} + \frac{y^2}{90^2} = 1\]

*And yes 50^2 = 2500 and 90^2 = 8100*

This would give a = 90 and b = 50 *since A is always the bigger of the two

Answer 13

And oh god no...much easier than that!

Answer 14

Wait you lost me...

Answer 15

Okay okay...dont look at anything above this point!

Answer 16

I thought before a was 50 now its 90

Answer 17

lol

Answer 18

We have the standard form of an ellipse

\[\large \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\]

\[\large \frac{x^2}{2500} + \frac{y^2}{8100} =1\]


One thing to know *I was testing you earlier!* is that 'a^2' is always the larger of the 2 denominators!

Meaning here we would have a^2 is ACTUALLY 8100 or a = 90
And b^2 is ACTUALLY 2500 or b = 50

Answer 19

From here, it is simply \(\large \text{Major Axis Length} = 2a\)

Answer 20

okay... how about this problem. We're not getting anywhere with you TESTING me.. bwahahha