Question

Find the function F(x), given that F'(x)=(6/x^2)- (10/x^6) and F(1)=0

Answer 1

\( F'(x)=\dfrac{6}{x^2} - \dfrac{10}{x^6} \)

\( F(x)=\int ~ \dfrac{6}{x^2} - \dfrac{10}{x^6} ~dx \)


\(F(1) = 0\)

Answer 2

nuff said ?!?!

Answer 3

So F(x)= (2/x^5) + (6/x) +C ??? @IrishBoy123

Answer 4

\(F(x)=\int ~ \dfrac{6}{x^2} - \dfrac{10}{x^6} ~dx\)
\(= \dfrac{2}{x^5} - \dfrac{6}{x} + C\)

\(F(1) = 0 \implies 0 = 2 - 6 + C \implies C = 4\)

\(F(x) = \dfrac{2}{x^5} - \dfrac{6}{x} + 4\)

Answer 5

Oh I see how that works now! Thank you!