Question

@mathmale .-. more help please?

Answer 1

Which of these 2 would be the harder for you? We'll focus on that one.

Answer 2

the top one

Answer 3

This subject is a bit abstract: inverse functions. I imagine you have drawn a sine function before. Have you? If so, what was the largest value that y=sin x could have? the smallest?

Answer 4

ummm isnt it... -2?

Answer 5

and 2?

Answer 6

No; the smallest value the sine function can take on is -1, and the largest is +1.
Again, that's for the SINE function. The problem y ou've posted involves the INVERSE SINE function, quite a different animal.

Answer 7

i think. I took a break from my math work and did like, two months of japanese and science. now im super lost

Answer 8

im sorry :/

Answer 9

You're learning, so I'm happy. And wow, learning Japanese!!

Answer 10

yup :) おはいよう　ございます　私は　ソッメル　です。　(Good morning my name is Sommer)

Answer 11

For reasons that I'll go into later if you wish, we have to restrict the sine function to the interval [ -pi/2 , +pi/2 ]. When the angle, x, is -pi/2, the value of the sine function is -1; when it's +pi/2, the value of the sine function is +1.

Answer 12

OHHHHHH okok SO ITS C?

Answer 13

Rule: the DOMAIN of the INVERSE of the SINE function is the same as the RANGE of the SINE function.

Answer 14

then that would mean that it is b because the largest it can be is -1 and 1 right?

Answer 15

Let's put it this way: \[-1\le \sin x \le +1\]

Answer 16

\[\frac{ -\pi }{ 2 }\le \sin ^{-1}x \le \frac{ \pi }{ 2}\]

Answer 17

The sine is periodic with period 2pi, and is defined for all x. However, if we want to find the inverse sine, we must restrict the inputs to sin x to [-1,1] (so that the resulting function is "one-to-one."