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Mathematics 10 Online
OpenStudy (jessicaloraine):

how do I find the foci of a parabola

OpenStudy (jessicaloraine):

how do I find 1/4a

OpenStudy (welshfella):

the focus can be found from the vertex form of the parabola y = a(x - h) + k

OpenStudy (welshfella):

note this is for a parabola with a vertical axis of symmetry

OpenStudy (jessicaloraine):

is it true that 1/4c=1

OpenStudy (welshfella):

it depends what you mean by c

OpenStudy (jessicaloraine):

I do know like the basic formula but I keep on getting a messed up answer according to the calculator

OpenStudy (jessicaloraine):

how do I find the c

OpenStudy (welshfella):

what formula are you talking about?

OpenStudy (jessicaloraine):

On the book, it mentions (h,k+c)

OpenStudy (jessicaloraine):

if the vertex is not on (0,0)

OpenStudy (jessicaloraine):

The equation I got was y=-3x^2+3

OpenStudy (welshfella):

tell me which formula you mean

OpenStudy (jessicaloraine):

y=1/4c(x-h)^2+k

OpenStudy (jessicaloraine):

Is a -3?

OpenStudy (welshfella):

Oh I'm sorry I got that wrong Its 1/4a not (1/4) a

OpenStudy (jessicaloraine):

thats ok

OpenStudy (welshfella):

lets find the focus of y = -3x^2 + 3 step by step

OpenStudy (jessicaloraine):

yes

OpenStudy (jessicaloraine):

that would be helpful

OpenStudy (welshfella):

first we convert the equation to vertex form there is no term in x so the equation becomes ( h = 0):- y = ax^2 + k so a = -3 , h = 0 and k = 3 focus = ( h k+ 1/4a) = (0, 3 + 1/4(-3)) = (0, 3 - 1/12) = (0, 35/12)

OpenStudy (welshfella):

any questions?

OpenStudy (jessicaloraine):

how is the equation y=ax^2+k

OpenStudy (welshfella):

well because h = 0 y = a(x-h)^2 + k our equation is -3 x^2 + 3 comparing this with the above standard form a = -3 and k = 3 but theres is no -h so h = 0

OpenStudy (welshfella):

if you like we can write out equation as y = -3 (x - 0)^2 + 3 comparing with y = a(x - h)^2 + k we see that h = 0.

OpenStudy (jessicaloraine):

Ohhh now I'm getting it

OpenStudy (welshfella):

good

OpenStudy (jessicaloraine):

and c= 1/4a?

OpenStudy (welshfella):

if you write the y coordinate of the focus as k +c then c = 1/4a Yes.

OpenStudy (jessicaloraine):

ok I think I'm good but I gotta make sure

OpenStudy (jessicaloraine):

I got up to y=-3x^2+3

OpenStudy (jessicaloraine):

so do I input K+1/4a into y?

OpenStudy (welshfella):

yes

OpenStudy (welshfella):

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