the focus can be found from the vertex form of the parabola
y = a(x - h) + k
OpenStudy (welshfella):
note this is for a parabola with a vertical axis of symmetry
OpenStudy (jessicaloraine):
is it true that 1/4c=1
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
it depends what you mean by c
OpenStudy (jessicaloraine):
I do know like the basic formula but I keep on getting a messed up answer according to the calculator
OpenStudy (jessicaloraine):
how do I find the c
OpenStudy (welshfella):
what formula are you talking about?
OpenStudy (jessicaloraine):
On the book, it mentions (h,k+c)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (jessicaloraine):
if the vertex is not on (0,0)
OpenStudy (jessicaloraine):
The equation I got was y=-3x^2+3
OpenStudy (welshfella):
tell me which formula you mean
OpenStudy (jessicaloraine):
y=1/4c(x-h)^2+k
OpenStudy (jessicaloraine):
Is a -3?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
Oh I'm sorry I got that wrong
Its 1/4a not (1/4) a
OpenStudy (jessicaloraine):
thats ok
OpenStudy (welshfella):
lets find the focus of y = -3x^2 + 3 step by step
OpenStudy (jessicaloraine):
yes
OpenStudy (jessicaloraine):
that would be helpful
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
first we convert the equation to vertex form
there is no term in x so the equation becomes ( h = 0):-
y = ax^2 + k
so a = -3 , h = 0 and k = 3
focus = ( h k+ 1/4a) = (0, 3 + 1/4(-3))
= (0, 3 - 1/12)
= (0, 35/12)
OpenStudy (welshfella):
any questions?
OpenStudy (jessicaloraine):
how is the equation y=ax^2+k
OpenStudy (welshfella):
well because h = 0
y = a(x-h)^2 + k
our equation is -3 x^2 + 3
comparing this with the above standard form
a = -3 and k = 3 but theres is no -h so h = 0
OpenStudy (welshfella):
if you like we can write out equation as
y = -3 (x - 0)^2 + 3
comparing with
y = a(x - h)^2 + k
we see that h = 0.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (jessicaloraine):
Ohhh now I'm getting it
OpenStudy (welshfella):
good
OpenStudy (jessicaloraine):
and c= 1/4a?
OpenStudy (welshfella):
if you write the y coordinate of the focus as k +c then c = 1/4a Yes.
OpenStudy (jessicaloraine):
ok I think I'm good but I gotta make sure
Still Need Help?
Join the QuestionCove community and study together with friends!