I don't understand how to do the next part would someone please help me? Solve the equation below
\[z-\frac{ 3 }{ 2 }=-\frac{ 5 }{ 6 }\]
To solve the equation, isolate the variable. Add 3/2 to both sides of the equation \[z-\frac{ 3 }{ 2 }+\frac{ 3 }{ 2}=-\frac{ 5 }{ 6 }+\frac{ 3 }{ 2 }\]
Add the fractions on the right side \[z=-\frac{ 5 }{ 6 }+\frac{ 3 }{ 2 }\]
You need to change the denominator of 3/2. Multiply the top and bottom by 3
I agree. The reason for this is that you must express all fractions with the same denominator before you can combine them.\[z=-\frac{ 5 }{ 6 }+\frac{ 3 }{ 2 }\]
Taking the 2nd fraction, mult. its numerator and its denom. both by 3, as aveline has suggested:\[\frac{ 3 }{ 2 }*\frac{ 3 }{ 3 }\]
Please share your result here.
Scarlett, I don't mean to egg you on, but to continue helping you, I need to hear back from you once in a while.
\[\frac{ 9 }{ 6 }\] would be the answer right? And sorry @mathmale I step away also thanks you @Aveline for your help too
z=-5/6+3/2 We change 3/2 to 9/6, so... \[z=\frac{ -5 }{ 6 }+\frac{ 9 }{ 6 }\]
By adding the together we get \[\frac{ 14 }{ 6}\] would that be the answer? Or am I doing something wrong?
But isn't -5+9 a small, positive number?
Just as mathmale said. Another way to write -5+9 is 9-5
Which would be 4
Yes, and so what is your final value for x? Write the equation x= ... ?
it would stay 6 wouldn't it?
z comes out to 4/6. Is there any way in which you could reduce this fraction?
\[\frac{ 4 }{ 6 }\div2 =\frac{ 2 }{ 3 }\]
While your answer is 100% correct, the method used isn't. Have to divide BOTH the 4 and the 6 by 2:\[\frac{ 4/2 }{ 6/2 }\]
Remember, you're dividing by 2/2, not just 2. However, your answer is correct. Good job
okay i see now I didn't step the problem up right would I divided by 2
Glad this conversation has led to better understanding for you. Take care, Scarlett!
Thanks @mathmale
You're welcome!
Thanks again @Aveline
Np
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