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Linearization of F(x), x= a f(x) = 1/(6x+2) a=0
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so i take the derivative and f(x) i get \[\frac{ 6 }{ (6x+2)^2 }\]
plug 0 into both f(x) and \[f \prime (x) \]
f(0) = 1/2 and f'(0) = -1.5 so plug into linearization formula \[L(x) = F(0) + F'(0)(x-n)\] this comes out to L(x) = 1/2 + (-1.5)(x-0) is that correct?
your derivative is wrong.
forgot the (-)
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yep!
oh, you solved using the negative but forgot to write it above yeah you're right
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