Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (goldandpinkiscool):

What is the equation of the plane in picture?

OpenStudy (goldandpinkiscool):

OpenStudy (goldandpinkiscool):

@Aishalicious1

OpenStudy (goldandpinkiscool):

@hartnn

OpenStudy (goldandpinkiscool):

@Astrophysics

OpenStudy (goldandpinkiscool):

@Tennis5518

OpenStudy (goldandpinkiscool):

So, anyone know???????

OpenStudy (anonymous):

Are you familiar with the cross product of vectors?

OpenStudy (goldandpinkiscool):

no

OpenStudy (anonymous):

humm... ok, thinking

OpenStudy (anonymous):

Could set up three equations with the three points you have.

OpenStudy (anonymous):

\[a(x-x_0)+b(y-y_0)+c(z-z_0)=0\\ a(x-x_1)+b(y-y_1)+c(z-z_1)=0\\ a(x-x_2)+b(y-y_2)+c(z-z_2)=0\] and solve for a,b,c

OpenStudy (goldandpinkiscool):

Cool but I don't even know how to read the point in the graph. It's so confusing.. @_@

OpenStudy (anonymous):

the points are on the axis, so you can just count out, e.g. one point is at (z,y,x)=(4,0,0)

OpenStudy (goldandpinkiscool):

okay here is what I think the other points are: y(4,0,0) and z(5,0,0)

OpenStudy (goldandpinkiscool):

Is that correct?

OpenStudy (anonymous):

I choose the normal the x,y,z order... so (4,0,0),(0,4,0),(0,0,5)

OpenStudy (anonymous):

Maybe try the simplified problem of finding the line through (4,0) and (0,4) first?

OpenStudy (anonymous):

So.. \[(y-0)=m(x-4)\\(y-4)=m(x-0)\]

OpenStudy (anonymous):

\[\frac{ x }{ 4 }+\frac{ y }{ 4 }+\frac{ z }{ 5 }=1~or~5x+5y+4z=20~or~5x+5y+4z-20=0\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!