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Mathematics 22 Online
OpenStudy (anonymous):

Verify the Pythagorean Identity.

OpenStudy (anonymous):

OpenStudy (math&ing001):

Are you familiar with the property sin²(x)+cos²(x)=1 ?

OpenStudy (anonymous):

not really, I don't really understand this stuff but if you would like to explain it and help me work it out I would be very grateful

OpenStudy (anonymous):

Sorry for the wait, I was working on another problem

OpenStudy (math&ing001):

It's OK. It's relevant to the Pythagorean Identity and the unit circle: |dw:1460399983734:dw| A number x in the unit circle coordinates' are (cos(x),sin(x)). From the drawing you can see that using the Pythagorean Identity, we get sin²(x)+cos²(x)=1

OpenStudy (math&ing001):

From that you just divide by sin²(x) to get the requested Pythagorean Identity.

OpenStudy (anonymous):

So it's like the Pythagorean theorem but different?

OpenStudy (anonymous):

I still don't understand how I would word that? Like sin²(x)+cos²(x)=1/sin^2(x)

OpenStudy (math&ing001):

It's exactly like Pythagorean theorem, applied to the unit circle.

OpenStudy (math&ing001):

No you have to divide both the RHS and the LHS ! 1/sin²(x) * (sin²(x)+cos²(x)) = 1/sin²(x) * 1 => 1 + cot²(x) = csc²(x)

OpenStudy (anonymous):

Okay I think I understand now

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