Question

bugatti

Answer 1

@imqwerty

Answer 2

okay 1st thing we have is this formula-

\(Magnitude= log_{10}\left(\large \frac{I_1}{I_0}\right)\)

\(I_0\) is constant and it denotes he intensity of 0 earthquake

Answer 3

yes ser

Answer 4

2nd-
we write down important stuff

\(M_e\) =magnitude of earthquake
\(I_e\) = intensity of earthquake

\(M_a\)=magnitude of aftershock
\(I_a\) =intensity of aftershock

Answer 5

yes ser

Answer 6

3rd-
we write down the info given to us-

"intensity" of earthquake is 39 times the intensity of aftershock
so-

\(I_e = 39 \times I_a\)

Answer 7

yes ser

Answer 8

4th-

for earthquake-
\(M_e=log_{10}\left(\large \frac{I_e}{I_0}\right)\)

we can write \(I_e\) as \(39 \times I_a\) so

\(M_e=log_{10}\left(\large \frac{39 \times I_a}{I_0}\right)\)
so
\(10^{M_e}= \large \frac{39 \times I_a}{I_0}\)

another equation which we can make is-
for aftershock-

\(M_a= log_{10}\left(\large \frac{I_a}{I_0}\right)\)
\(10^{M_a}=\large \frac{I_a}{I_0}\)

Answer 9

brb reloading

Answer 10

yes ser

Answer 11

okay so now we have 2 equations

1-
\(10^{M_e}= \large \frac{39 \times I_a}{I_0}\)

and 2-
\(10^{M_a}=\large \frac{I_a}{I_0}\)

try to solve them to get \(M_a\)

Answer 12

yes ser