Question

Can someone walk me through this Stoichiometry problem, how many grams of H2O will be produced by 58.2L of CH4 at STP? Assume an excess of O2

Answer 1

CH4 +2O2---------->CO2+2H2O
22.4 L CH4------------------2X18 gr H2O
58.2 L CH4------------------>?
58.2 X 36/22.4 =93.5 gr of water produced

Answer 2

does that answer ?

Answer 3

wait how do you get 22.4L CH4?

Answer 4

if u want it in simpler terms

Answer 5

How many grams of H2O will be produced by 58.2 L of CH4 at STP? Assume an excess of O2?
--------------------------------------...
58.2 liters CH4/22.4 liters/mole = 2.60 moles CH4

CH4 + 2O2 ----> CO2 + 2H2O

so 2 moles water/1 mole methane x 2.6 moles = 5.2 moles H2O

Answer 6

idk got it from an online calculator XD

Answer 7

you have to convert it to moles, this is how far I would get, 58.2L CH4 x 1 Mole of CH4/16.04g CH4...?

Answer 8

CH4(g) + 2 O2(g) ----> CO2 (g) + 2H2O(l)

Answer 9

hmmm

Answer 10

im srry maybe someone lese canhelp u im not really good at chemisty

Answer 11

thanks anyway, I'll figure it out, just getting impatient haha

Answer 12

@Matt6288 the first step is to balance your chemical equation.