Question

Question in attachment

Answer 1

@123AB456C @Directrix @Mehek14 @ScarlettFarra2000

Answer 2

need help quick

Answer 3

I want to say the answers B or C can't really help right now just leaving school I'll help when i get home

Answer 4

ok

Answer 5

@math&ing001 @truwhovian11

Answer 6

do u @math&ing001 or @Redcan know?

Answer 7

wWe can divide it to 4 figures like this.
Find the areas of each figure, then sum them up.

Answer 8

but idk what the mesurments for 2 numbers that = 21

Answer 9

I agree, divide it up works, and in this case you can also find the area of the big square - area of missing triangle

Answer 10

or maybe it doesnt matter cuz they both are going to be times by 4 anyways?

Answer 11

Yes that's what I've been trying to figure out. I mean I know a method, but I don't know if you already seen it or not. Have you seenthe Intercept theorem ?

Answer 12

21 * 9 = 189
4 * 18 = 72
4 * 3 = 12

Answer 13

idk maybe

Answer 14

it matters for the triangles. try

Answer 15

21 * 9 = 189
4 * 18 = 72 /2 = 36
4 * 3 = 12 /2 = 6

189 + 36 + 6 = 228

Answer 16

i forgot to divide them in half the triangles

Answer 17

21*13-1/2(4*21)

Answer 18

Yeah I think @Redcan 's method works best.

Answer 19

21*13-1/2(4*21)

21 * 13 - 1/2 (4 * 21)
21 * 13 - 1/2 (84)
273 - 42 = 231

Answer 20

is that correct?

Answer 21

@Redcan

Answer 22

Yep, correct !

Answer 23

ty!

Answer 24

=)