Use technology to find the probability associated with the cumulative area to the left of the z score of the adjusted value of x, 4.5 rounding to four decimal places. P(z<-0.7907)=0.2146 I am just unsure of how to get the 0.2146 from the P(z<-0.7907).
hm let me ask my friend google he might know
he's being a booch today, sorry can't help u
Sounds as tho' you're supposed to evaluate this probability using your calculator. Would you happen to have access to a TI-83 or -84?
Lol! Thanks anyway, Boldjon. I don't have either, but my professor told us that we shouldn't need one. :/
I checked that it is correct using a table of quantiles. Is it considered technology? What is this `4.5` in the statement?
If we focus on P(z<-0.7907)=0.2146 alone, not considering what that '4.5' represents, then our task is to find the area under the standard normal curve to the left of z=-0.7907. If you don't have a suitable calculator, then your best (and perhaps only) bet is to use a z-score table. Use the one that displays negative z scores, corresponding to areas to the left of the mean of your standard normal distribution. Find "-0.7" in the leftmost column, and then 0.09 or 0.091 in the topmost row. In the body of the table, underneath, you should see 0.21 or something similar. Do you have a table of z-scores available? If not, please have a look at these search results: http://www.bing.com/search?q=z-score+chart&src=IE-SearchBox&FORM=IESR02&pc=EUPP_UE02 Let me know how this works out for you.
Join our real-time social learning platform and learn together with your friends!