Can someone help me with this problem? A carnival ride is in the shape of a wheel with a radius of 30 feet. The wheel has 30 cars attached to the center of the wheel. What is the central angle, arc length, and area of a sector between any two cars? Round answers to the nearest hundredth if applicable. You must show all work and calculations to receive credit.
@robtobey can you help?
Ok, there are 360 degrees in a circle (or 2pi radians). So since there are 30 cars, each angle is 360 degrees/30, or 2pi/30
so i would divide 360by30?
Yes.
12
Yes, I think that's what they're asking for when they say central angle.
And it's 12 degrees.
Do you know how to find arc length?
No.. sorry
@anthonyym how do i find the arc length
Do you know what radians are?
They sound familiar.
Have you been taught that yet?
Maybe i am not sure.
Well, arc length formula is \[S = \theta r\] S is arc length, θ (theta) is angle, r is radius. And theta is in radians.
oh yes! i remember that.
So to convert the angle to radians (it's currently 12 degrees), you multiply by 2pi/360, or pi/180.
\[\frac{ 12° }{ 1 }*\frac{ \pi }{ 180° }\]
ok so i would do 12x3.14 and 1x180 right?
Yes, in other words (12pi)/180
Ok
Or, you could have found the angle in radians from the beginning. A circle is 360 degrees, or 2pi radians. So you could have found the angle between each car in radians by doing (2pi)/30
so is 12pi/180 the arc length?
No, that's the angle in radians
oh ok.
To find arc length, the formula is S=angle[in radians]*radius, where S is the arc length.
We converted the angle to radians because it was in degrees and the formula requires the angle to be in radians.
Oh ok that makes sense
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