Question

5

Answer 1

50 mL of water = 850 g of water assuming a density of 1.0 g/mL

molality = moles of solvent / mass of water in kg

moles of solvent (Ca(OH)2) = molality * mass of water in kg.

Multiply moles of Ca(OH)2 by the molar mass of Ca(OH)2

You should get 151,4 g.

Answer 2

@itsmichelle29 is what @malijhaa said clear?

Answer 3

no problem. so you know that molarity is

\[Molarity = \frac{ Moles }{ L }\]

Answer 4

Okay If Its Not Clear Let Me Knw. Yhu Dont Have To Be Rude About It. It Was Obviously A Mistake :)

Answer 5

It Was A Mistake Because It Didnt Help Yhu :)

Answer 6

do you see the figure I drew above?

Answer 7

yep 2.4*.81

Answer 8

then you would get the number of moles.

Answer 9

then multiply by the molar mass of CaOH

Answer 10

Correction \[Ca(OH)_{2}\]

Answer 11

yes