Question

1/8 +2/t=17/8t
I need step by step help

Answer 1

Let's solve your equation step-by-step.
1
8
+
2
t
=
17
8
t
Multiply all terms by t and cancel:
1t
8
+2=(
17
8
t)(t)
1
8
t+2=
17
8
t2(Simplify both sides of the equation)
1
8
t+2−
17
8
t2=
17
8
t2−
17
8
t2(Subtract 17/8t^2 from both sides)
−17
8
t2+
1
8
t+2=0
t=
−b±√b2−4ac
2a
(Use quadratic formula with a=-2.125, b=0.125, c=2)
t=
−(0.125)±√(0.125)2−4(−2.125)(2)
2(−2.125)
t=
−0.125±√17.015625
−4.25
t=−0.9411764705882353,1
Check answers. (Plug them in to make sure they work.)
t=−0.941176(Works in original equation)
t=1(Works in original equation)

Answer 2

Answer:
t=−0.941176 or t=1

Answer 3

@malijhaa aren't you using http://mathpapa.com/algebra-calculator.html..

Answer 4

Yess

Answer 5

\(\large \frac{1}{8} + \frac{2}{t} = \frac{17}{8t}\)

Find the common denominator. What would that be?
(Hint: multiply the two denominators)

Answer 6

\(\large \frac{1}{8} + \frac{2}{t} = \frac{17}{8t}\)

Multiply 8 \(\times\) t to get \(8t\)

Make sure that each of the fractions are equivalent to have the denominator of 8t.

\[\large (\frac{8t}{1} \times \frac{1}{8}) + (\frac{8t}{1} \times \frac{2}{t} ) \rightarrow \color{red}{\frac{t}{8t} + \frac{16}{8t}}\]

Answer 7

@calculusxy explained much bette than @malijhaa who just copied and pasted it~

Answer 8

\(\large \color{red}{\frac{t}{8t} + \frac{16}{8t} = \frac{17}{8t}}\)

Now since all of the them have the common denominator of 8t, then we can simply solve for t algebraically.

\(\color{green}{t + 16 = 17}\)
\(\color{green}{t + 16 - 16 = 17 - 16}\)
\(\large \color{green}{t = 1}\)

Answer 9

@AloneS right

Answer 10

I think that this method is much easier compared to using the quadratic formula.

Answer 11

@babybritt002 medal him ;)